(1)5ax+5bx+3ay+3by 解法:=5x(a+b)+3y(a+b) =(5x+3y)(a+b) (2)x^3-x^2+x-1 解法:=(x^3-x^2)+(x-1) =x^2(x-1)+ (x-1) =(x-1)(x^2+1) (3) x2-x-y2-y 解法:=(x2-y2)-(x+y) =(x+y)(x-y)-(x+y) =(x+y)(x-y-1)
(4)bc(b+c)+ca(c-a)-ab(a+b) =bc(c-a+a+b)+ca(c-a)-ab(a+b) =bc(c-a)+bc(a+b)+ca(c-a)-ab(a+b) =bc(c-a)+ca(c-a)+bc(a+b)-ab(a+b) =(bc+ca)(c-a)+(bc-ab)(a+b) =c(c-a)(b+a)+b(a+b)(c-a) =(c+b)(c-a)(a+b). (5)x^2+3x-40 =x^2+3x+2.25-42.25
=(x+1.5)^2-(6.5)^2 =(x+8)(x-5).
(6)(x^2+x+1)(x^2+x+2)-12时,可以令y=x^2+x,则 原式=(y+1)(y+2)-12
=y^2+3y+2-12=y^2+3y-10 =(y+5)(y-2)
=(x^2+x+5)(x^2+x-2) =(x^2+x+5)(x+2)(x-1).
(7)(1+y)^2-2x^2(1+y^2)+x^4(1-y)^2 解:原式
=(1+y)^2+2(1+y)x^2(1+y)+x^4(1-y)^2-2(1+y)x^2(1-y)-2x^2(1+y^2)
=[(1+y)+x^2(1-y)]^2-2(1+y)x^2(1-y)-2x^2(1+y^2) =[(1+y)+x^2(1-y)]^2-(2x)^2
=[(1+y)+x^2(1-y)+2x]·[(1+y)+x^2(1-y)-2x] =(x^2-x^2y+2x+y+1)(x^2-x^2y-2x+y+1) =[(x+1)^2-y(x^2-1)][(x-1)^2-y(x^2-1)] =(x+1)(x+1-xy+y)(x-1)(x-1-xy-y) (8)(2a-b)²+8ab=(2a+b)²
(9)y²-2y-x²+1=(y-1)²-x²=(y-1-x)(y-1+x) (10)x²-xy+yz-xz =x(x-y)-z(x-y)=(x-z)(x-y) (11)6x²+5x-4 =(2x-1)(3x+4)
(12)2a²-7ab+6b²=(2a-3b)(a-2b)
(13)(x²-2x)²+2(x²-2x)+1 =(x²-2x+1)²=(x-1)^4 (14)(x²-2x)²-14(x²-2x)-15 =(x²-2x-15)(x²-2x+1)=(x+3)(x-5)(x-1)²
(15)x²(x-y)+(y-x) =(x²-1)(x-y)=(x+1)(x-1)(x-y) (16)169(a+b)²-121(a-b)²
=(14a+14b-11a+11b)(14a+14b+11a-11b) =(3a+25b)(25a+3b)
(17)(x-3)(x-5)+1 =(x-3)²-2(x-3)+1 =(x-3-1)²=(x-4)² -5a^2+16a=a(16-5a) (18)8x^2-4x=4x(2x-1) (19)15p+10p^2=5p(3+2p) -3x^2y-6xy=-3xy(x+2y)
(20)14m^3n^2-6m^2n^3=2m^2n^2(7m-6n) (21)27a^2 b^3 c+18ab^2=9ab^2(3abc+2) (22)18xy^2 z^3+12x^2 y^2=6xy^2(3z^3+2x) (23)8m^2 n^2 -6m^3 n^2=2m^2 n^2(4-3m) (24)x^5+3x^4y-5x^3y^2+4xy^4+12y^5
解:原式=(x^5+3x^4y)-(5x^3y^2+15x^2y^3)+(4xy^4+12y^5) =x^4(x+3y)-5x^2y^2(x+3y)+4y^4(x+3y) =(x+3y)(x^4-5x^2y^2+4y^4) =(x+3y)(x^2-4y^2)(x^2-y^2)
=(x+3y)(x+y)(x-y)(x+2y)(x-2y) (25)分解因式m +5n-mn-5m 解:m +5n-mn-5m= m -5m -mn+5n = (m -5m )+(-mn+5n) =m(m-5)-n(m-5) =(m-5)(m-n)
(26)因式分解(2x+1)(x+1)+(2x+1)(x-3)=2(x-1)(2x+1) (27)因式分解2ax2-3x+2ax-3=(x+1)(2ax-3) (28)因式分解x(y+2)-x-y-1=(x-1)(y+1) (29)因式分解(x2-3x)+(x-3)2=(x-3)(2x-3) (30)因式分解9x2-66x+121=(3x-11)^2
(31)已知,2x2-Ax+B=2(x2+4x-1),请问A、B的值是多少? 解:2x2-Ax+B=2(x2+4x-1)= 2x2+8x-2 所以A=-8,B=-2.
(32)若2x2+mx-1能分解为(2x+1)(x-1),求m的值。 解:2x2+mx-1=(2x+1)(x-1)= 2x2-x-1所以mx=-x 即m=-1.
(33)已知a+b=5,ab=7,求a2b+ab2-a-b的值。 解:a2b+ab2-a-b =ab(a+b)-(a+b) =(a+b)(ab-1)
把a+b=5,ab=7代入上式,原式=30.
(34)已知a2b2-8ab+4a2+b2+4=0,求ab的值。 解:将a2b2-8ab+4a2+b2+4=0变形得
a2b2-4ab+4+4a2-4ab+b2=0;(ab-2)2+(2a-b)2=0 所以ab=2,2a=b解得:a=±1,b=±2. 所以ab=2或ab= -2.
(35)请问9910-99能被99整除吗?说明理由。 解:9910-99=99(999-1)
所以9910-99能被99整除,结果为999-1.
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